+865 In an equation of the form k = ax^2 + bx + c with a > 0, the least possible value of k occurs at x = -b/(2a). In the equation k = (6x + 12)(x - 8), what is the least possible value for k?
From your formula, x = (-36)/(2) = -18, so the minimum value of k is (6(-18) + 12)((-18) - 8) = 2496.
+23246 y = (6x + 12)(x - 8) ---> y = 6x2 - 48x + 12x - 96 ---> y = 6x2 - 36x - 96
a = 6 b = - 36 c = - 96
Using the formula: x = - b / (2a) ---> x = - -36 / (2 · 6) ---> x = 36 / 12 ---> x = 3
Place this back into the equation y = (6x + 12)(x - 8) ---> y = (6·3 + 12)(3 - 8) ---> y = 30 · -5
---> y = -150
