Find all real numbers t such that \($\frac{2}{3} t - 1 < t + 7 \le -2t + 15$\). Give your answer as an interval.
Find all real numbers t such that \(\frac{2}{3} t - 1 < t + 7 \le -2t + 15 \). Give your answer as an interval.
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\(\frac{2}{3} t - 1 < t + 7 \le -2t + 15\\ -8 <\frac{1}{3}t\\ \color{blue}t<24\)
\( \)
\(t+7\le-2t+15\\ -8\le -3t\\\color{blue}t\le24\)
\(t\in \{ \mathbb{R}|t<24\}\)
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Find all real numbers t such that \(\frac{2}{3} t - 1 < t + 7 \le -2t + 15 \). Give your answer as an interval.
Hello Guest!
\(\frac{2}{3} t - 1 < t + 7 \le -2t + 15\\ -8 <\frac{1}{3}t\\ \color{blue}t<24\)
\( \)
\(t+7\le-2t+15\\ -8\le -3t\\\color{blue}t\le24\)
\(t\in \{ \mathbb{R}|t<24\}\)
!
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Answers by CPhill and me: | https://web2.0calc.com/questions/help_49470 | |
Second answer by CPhill: |
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Answer by heureka: | ||
Second answer by me: |
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Found from first page of search results here. |
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