+2094 How many odd five-digit counting numbers can be formed by choosing digits from the set [1,2,3,4,5,6,7] if digits can be repeated?
+128399 The 5 digit number will end in either 1, 3, 5 or 7
Since digits can be repeated we have 7 choices for each of the 4 leading positions and 4 choices for the ending digit
So....the total number of odd five-digit countig numbers =
7^4 * 4 =
9604
+36914 A different perspective...just an FYI
75 possible numbers 4 out of 7 are odd 75 x 4/7 = 9604 (as Chris calculated)
+118608 Cal has told me that this wasn't actually her question.
The system is sometimes capturing her username and assigning it to guest questions that have just been posted.
I assume she is on shared wifi or something like that.
Anyway she says she is glad it happened this time because she learned a lot from EP and Chris who so kindly answered this question.
Thanks guys 
It is so nice to know that we have genuine learners here. Thanks Cal.
