+1161 If \(f(x) = \begin{cases} 2x-5 &\quad \text{if } x \ge 3, \\ -x + 5 &\quad \text{if } x < 3, \end{cases} \)
then for how many values of x is \(f(f(x)) = 3\)?
+288 I think it would be a good idea if you solve this for yourself. :)
Do some casework!
Set up some cases such as x >= 3, and where x < 3. Remember, just because x >= 3, doesn't mean that f(x) is also greater than or equal to 3, set up some cases there too! There may also be extraneous solutions! Get rid of those :)
