+318 Let f(y)=70+a(2^ky) with f(0)=80 and f(1)=150
Find value of a and k and then evaulate the function f(2)
stuck on this for 30 minutes someone please give the answer :( thanks so much
value of a=
value of k=
f(2)=
+128407 I'm assuming that this is ⇒ f(y) = 70 + a(2)^(ky)
f(0) = 80 implies that
80 = 70 + a(2)^(k*0)
80 = 70 + a(2)^(0)
80 = 70 + a(1)
80 = 70 + 10 a =10
f(1) =150
Which implies that
150 = 70 + 10 *(2)^(k* 1) subtract 70 from both sides
80 = 10 * (2)^(k) divide both sides by 10
8 = 2^(k)
Note that since 2^3 = 8 then ⇒ k = 3
f(2) = 70 + 10 (2)^[ 3 * 2]
f(2) = 70 + 10(2)^6
f(2) = 70 + 10*64
f(2) = 70 + 640
f(2) = 710
