flflvm97

Ask gently.

10+9=19

I think it's question on calculation with time.

Then it should be 8:10.

Thank everyone.

I will keep upload my questions daily.

And thanks to Melody for suggesting such opportunity, 

but I'm not sure if I can handle it. 

I would love to, maybe later days?

Anyway, thanks for all the attentions!

Good one :)

Phil

Um...I just want to have fun and motivate.

If you don't like it, pls just pass by.

thank you

According to your question, we are finding the height of second bounce.

If I say it's s, 

the u(initial velocity) of first bounce should be 0, because you said you are dropping, not adding force.

the v(final velocity) of first bounce should be u(initial velocity) of second bounce.

and the ball at peak of second bounce, the speed should be 0.

if we work out the acceleration by F=ma, (or if time or acceleration is given and you didn't mention) then we can work out s. By formula $${{\mathtt{v}}}^{{\mathtt{2}}} = {{\mathtt{u}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{as}}$$

$$0=(u_1) ^2+2as$$ (I'm setting peak of second bounce as end)

It's just like inches and meters.

Sorry Z, My explanation was not good enough to make you understand.

Sometimes, it's hard to explain even you understood.

Thank you anyway!

I don't understand you, and 1/3 + 1/2 does not equal 2/3.

To explain further, you can use your common sense to get the gut.

If there are 100 billion doors, 99 billion doors are toy cars, and 1 door is sports car.

If you randomly choose one, it's really unlikely to get sports car.

After you choose, host opened all the door with toy cars except one door and the door you chose.

Which one is likely to be sports car?

Use your common sense.