2002^2002. Last week I took a test and I got this question 20002^2002. The question didn't ask for the result, it ask for the last number of 2002^2002. The options are : A.0 B.2 C.4 D.8. I answered C.4. Am I right or not?
Note the pattern.......
2^1 = 2
2^2 = 4
2^3 = 8
2^4 = 16 and then this pattern of the ending digit starts all over again
So, dividing 2002 by 4, we have 500 + 2/4 ....this tells us that the number will end with the second digit in the pattern, i.e., ..... 4
You are correct !!!!!