Hi
I have a sum invested. Say 1000 dollars.
This sum will rise in value for 10 years with 10% per year. 1000*1.1^10. but I also want to add 100 dollars per year for 10 years and that amount will also rise in value by 10% per year.
Can someone plz help me with a complete formula for this? Thank you.
This sum will rise in value for 10 years with 10% per year. 1000*1.1^10. but I also want to add 100 dollars per year for 10 years and that amount will also rise in value by 10% per year.
Can someone plz help me with a complete formula for this? Thank you.
Well if the 100 is put in at the beginning of each year for 10 years
The the first 100 will grow to 100*1.1^10
The the first 100 will grow to 100*1.1^9
The the last 100 will grow to 100*1.1^1
The addition will be
$$\\100*1.1^1+100*1.1^2+ .....100*1.1^{10}\\
=100(1.1+1.1^2+ ......+1.1^{10})\\\\
$This is a GP a=100*1.1, r=1.1$\\\\
sum = \frac{a(r^n-1)}{r-1}\\\\
sum = \frac{100*1.1(1.1^{10}-1)}{1.1-1}\\\\
sum = \frac{100*1.1(1.1^{10}-1)}{0.1}\\\\$$
So total after 10 years (all deposits are made at the beginning of the relevant year)
Grand Total = $$1000*1.1^{10}+ \frac{100*1.1(1.1^{10}-1)}{0.1}\\\\$$
This sum will rise in value for 10 years with 10% per year. 1000*1.1^10. but I also want to add 100 dollars per year for 10 years and that amount will also rise in value by 10% per year.
Can someone plz help me with a complete formula for this? Thank you.
Well if the 100 is put in at the beginning of each year for 10 years
The the first 100 will grow to 100*1.1^10
The the first 100 will grow to 100*1.1^9
The the last 100 will grow to 100*1.1^1
The addition will be
$$\\100*1.1^1+100*1.1^2+ .....100*1.1^{10}\\
=100(1.1+1.1^2+ ......+1.1^{10})\\\\
$This is a GP a=100*1.1, r=1.1$\\\\
sum = \frac{a(r^n-1)}{r-1}\\\\
sum = \frac{100*1.1(1.1^{10}-1)}{1.1-1}\\\\
sum = \frac{100*1.1(1.1^{10}-1)}{0.1}\\\\$$
So total after 10 years (all deposits are made at the beginning of the relevant year)
Grand Total = $$1000*1.1^{10}+ \frac{100*1.1(1.1^{10}-1)}{0.1}\\\\$$