Since both equations = 1, we have
x + y + z = 2xy - z^2 or, alternatively
x + y - 2xy + z^2 + z = 0
As Melody indicates, because we have more variables than equations, there are infinitely many solutions.....
The graph of this is a "two-sheeted" hyperboloid....... here it is displayed in WolframAlpha
Since both equations = 1, we have
x + y + z = 2xy - z^2 or, alternatively
x + y - 2xy + z^2 + z = 0
As Melody indicates, because we have more variables than equations, there are infinitely many solutions.....
The graph of this is a "two-sheeted" hyperboloid....... here it is displayed in WolframAlpha