ElectricPavlov

First, reduce/simplify the quadratic to:

-x^2 -25x +4      This is a dome shaped parabola 

put it into vertex form to find the highest point

-1 ( x^2 + 25x) =  y -4 

-1 ( x+12.5)^2   = y-4 - 156.25

-1 ( x+12.5)^2  = y + 160.25          shows vertex is   -12.5, 160.25

So the y-values this parabola can have ( the range)   is     ( - inf, 160.25]             

I believe that would be '16' with factors   1 2 4 8 16 

North = 0 degrees 

   turn 45 degrees R    then 45 degrees L  and it is agan facing north .....then turn 'x' = 180 degrees to face south

See image below:

630 divided by 42 = 15     the other two integers, when multiplied = 15    so  either they are   3 and 5   or   1 and 15 

(d-7) = 9 (g-7)     Given

(d-4) = 6 (g-4)      Given       <==== solve for   g= (d+20)/6     <==== use THIS in the first equation 

d-7 = 9 ( (d+20)/6   - 7)       Solve for   d

d-7 = (9d+180)/6 - 63 

d+56 = (9d+180)/6 

6d + 336 = 9d + 180 

156 = 3d 

d = 52 y/o  now