ElectricPavlov

Seriously doubt that the distance to the 'hypothesis' is 14 .....longer than either of the legs...longer than the hypotenuse (13) .....

Posted yesterday or so...I think Geno answered it....try a search...

12 x 80 = 960 m²

960 m² / [( .3048 m/ft)(.3048 m/ft)] = 10333.35 ft²

10333.354 ft² / 200ft²/gal = 51.667 gal =~~52 gallons

5005 digits / 55 min = 91 dig /min

Will covers some of the distance (5 minutes worth ) before Grace starts

    50 m/mim X 5 min = 250 meters

       there is 2350 - 250 = 2100 meters to cover before they meet

The are approaching each other at   (50 + 10) = 60 m/min

    the time to cover 2100 M      is        2100 m / (60 m/min) = 35 mintes

2:05 + 35 min == 2:40   when they meet

8 C 3   *   6 C 2 = ........... ways

or

8! / ( 5! 3!)  *  6! / (4! 2!) = ....... ways

I edited it.....make sure you have most recent answer ! 

Answered.....

Find the trapezoidal area

10 x (8+12)/2    = 100 in²

volume =  100 in²  x 20 in = 2000 in³

10 times per month x 12 months = 120 times per year

120 x 2000 = 240  000 in³       which converts to 138.89 cu ft per year

138.89 ft³ / 1.25 ft³/bag = 111.11 bags per yer ~~ 111 bags/yr

Hang in there .....it gets easier !