ElectricPavlov

I'm having bacon and pepperoni on my veggie burger......   haha   ( saw that on a tweet today)

WHY ?????   There are big number calculators you can find online all over the internet.......that is just a lot of zeroes after the 73....

The car is travelling to the EAST at a constant rate (60km/hr) before it begins to DECCERATE to the WEST at a rate of 5 x 10^3  cm/s^2.

FIRST: The mass of the car is irrelevant....this is just 'smoke' to mislead you or see if you really know how to solve the problem.

SECOND:  Get everything into the same units...lets use the decceleration units of cm/s^2

  60 km/hr  x 1000m/km x100cm/m   /   3600 s/hr   = 1666.667 cm/s

xf= xi + vt + 1/2 a t^2       we know  v = 1666.667 cm/sec   and  a = -5 x 10^3 cm/s^2

   We need to find  t  to solve this equation

We (should ) know     vf= vfinal = 0 (because the car stops) = vi  + a t       If we substitute into THIS equation, we can find  t to solve the FIRST equation and find xf

vf = 0 = 1666.667   +  (-5 x 10^3) t       yields    t = .333 sec

Substitute this  't' into the first equation to solve for xf

xf = xo + vt + 1/2 a t^2

    = 0   + 1666.667 (.333) +  1/2 (-5 x 10^3)(.333^2)   =   277.77 cm = 2.778 meters

To stop from 60 km/hr in 2.778 meters is pretty impressive!!!

Tha will always be the case when you neglect air friction and there are no other forces besides gravity acting on the object.

You are given   64 words   and  8 minutes and you want   words/minute

so just divide the two       64 words/ 8 minutes = 8 words/min = 8 words per minute

it goes up in 1/2 of the total time....it comes down in the other half of the time.

1/2 of the time is 1.75 secs

vf=vi+at  to find  vi    (velocity initial)  vf= 0 (because it stops and begins to fall back down)

then use

Use   xf=xi + vt + 1/2 at^2    to find xf (the final height)   with xi = initial height = 0

vf=0 = vi + (-9.8)( 1.75)   yields vi = 17.15 m/s

xf = xi + 17.5(1.75) + 1/2(-9.8)(1.75)^2

xf= 0 + 30.625 - 15.006=  15.619 m

Do you mean   e^3.13  ?    then 'e' is the opposite of the natural log (ln)   e= 2.71828

e^3.13 = 22.874

To 'answer a right triangle'  do you mean:  See if it IS a right triangle?

If it IS a right triangle, then pythagorean theorem applies   

a^2 + b^2 = c^2

where a and b are the 'legs'  which are the shorter two of the three side measurements and c is the hypotenuse....the longest side measurement.

THAT is an EXPRESSION....not anything I can do with that.

When you add an EQUAL sign it becomes an EQUAtion   (get it?)

3x+9 + y  =  7    is an EQUAtion WITH two variables  x and y.

to solve equations , you have to have an equation for each VARIABLE.....two equations, two variables......or you can SOLVE for ONE of the variables...but you cannot get a numerical value for the variable

example

solve 3x+9 + y =7      for 'y'    that means : Manipulate the given equation until you have y= on one side

3x+9+y=7    Subtract 3x from both sides of the equation (this still makes it EQUAL)

3x-3x +9 + y = 7-3x

9+y = 7 - 3x      (because...well 3x-3x is zero)

Now subtract  '9' from both sides

9 - 9 + y = 7-3x - 9

y=7-3x-9

y=-2-3x    and you have solved the equation  FOR 'y' in TERMS of 'x''.....

Can't  do much with what you have given us......got more info?

7x = +- 28

x = 4 or -4