ElectricPavlov

24  v  42        11 years

error

1  /    1/2   =   1  x  2/1 = 2

Not sure what you INTENDED to ask, but here are a few possibilities

210 hr   x  1 day/24hr  = 8.75 days

210 hr   x 60 min/hr     = 12,600 minutes       

210 hr   x 60 min/hr  x 60 sec/min= 756,000 sec

41/99 =  41 divided by 99......just use the calculator on this website...you can do it!

- (x+y) = (-1)(x+y) = -x - y

Given a = -5 ft/sec^2

and xf = 45     and   t = 1        find vo

xf = xo + vot + 1/2 a t^2          xo = 0

45 = vo (1) + 1/2 (-5) 1^2       yields vo = 47.5 ft/s

Find TIME to stop  given  vo = 47.5 ft / s      a = -5 ft/s^2    and vf=0 (the car has stopped)

vf = vo + a t

0 = 47.5 - 5 t    yields  t = 9.5 s

Find DISTANCE to stop given  vo=47.5 ft/s  a = -5 ft/s^2   and  t= 9.5 s

xf=xo + vo t + 1/2 a t^2        xo=initial position being measured from = 0

xf = 47.5 (9.5) + 1/2 (-5)(9.5^2)    Yields   xf = 225.625 ft  to stop

First, the volume of the cube has to be in cm^3   not cm^2

Second.....there needs to be a diagram or something....missing?

You're welcome, of course!

Divide them to find out

5.7 x 10^9  / 3 x 10^8   =  1.9 x 10^1 = 19 times larger