- x^2 -x + 3 = 2x^2 -1 re-arrange
0 = 3x^2 +x-4 use quadratic formula to find the x values where the graphs intersect
a = 3 b = 1 c = -4
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
use the x values in the equations to calculate the corresponding 'y' values
(actually....you will only need the 'x' values which will be c and a )
...then you can answer the rest of the question