1) P1 = 1,2 x = 1 y = 2 1 = 2t+1 so t = 0 as a check: y = 2 = 3(0)+2 = 2 CHECK !
you should be able to calculate P2 P3 and P4 in th same manner
re-write as
6t^2 - 41t + 30 = 0
Use Quadratic formula with a = 6 b=-41 c= 30
\(x = {-(-41) \pm \sqrt{(-41)^2-4(6)(30)} \over 2(6)}\)
to find x = 6 and x = 5/6 You can finish.....
5!
6! = 6 * 5!
so the greatest common factor is 5! = 120
Twice a 10 degree increase is 20 degrees
10 + 20 = 30 degree increase from 8 am to 4 pm
-14 + 30 = 16 degrees F at 4 pm
tan 20 = opposite side / adjacent side = 6oo/ d
d = 600/ tan20o = __________ ft
How about x = 1 ?
f(1) = 0
Using Law of Sines
sin 60 / 12 = sin b / 10
b = 46.194 degrees
angle A = 180 - 46.194 - 60 = 73.8059 degrees
12 / sin 60 = a / sin 73.8059
a = 13.31 units
x ( y + 4) = -7 - 2y
x = (-7-2y) / (y+ 4) y cannot equal -4
x and x+1 are the numbers
x^2 + 4 (x+1) = 64
x^2 + 4x -60 = 0
(x+10)(x-6) = 0 x = -10 or 6 take 6 since we are looking for positive integers then x+1 = 7
There will be TWO for each 360 degrees
3600 / 360 = 10 sets of 360 degrees
10 * 2 = 20 values
