Always negative.
I will assume you meant the store sold 40% of the original total on day 2 (not 40% of what was left after selling 15% on day one)
40 + 15% = 55% sold 45% remains = 142.8 kg
45/100 (x) = 142.8
x= original amount = 142.8/.45 = 317.333 kg
-3 * sqrt(8) - sqrt(18) =
-3 sqrt(4 x 2) - sqrt(9 x 2) =
-3(2)sqrt2 - 3 sqrt2
-6sqrt2-3sqt2= -9sqrt2
The one with the greater MAGNITUDE wins...
Wise Old Owl says "three"
That is not a sum, that is a ''product'
9.1058258 x 10^0
(-10 2/7 ) / (-4 4/11) = (-72/7) / (-48/11) = 72/7 x 11/48 = 792/336 =33/14 = 2.35714
=9 x 5.6 x 10^(5+8) = 50.4 x 10^13
4 \(\sqrt{2}\) / 2 = 2 \(\sqrt{2}\) = 2.8284
3/10(x+2)=12 Multiply through by the 3/10 to get
3/10x + 6/10 = 12 Subtract 6/10 from both sides of the equation
3/10x = 11 4/10 Multiply both sides by 10/3
x = 114/10 * 10/3
x = 114/3 = 38
