x^2+2y-9=-y^2+28x+19 re-arrange into circle form (x-h)^2 + (y-k)^2 = r^2
x^2 -28x + y^2 + 2y = 28 complete the square forx and y
(x-14)^2 + (y+1)^2 = 196 + 28 + 1
center = 14, -1 r = sqrt (196+28+1) I think you can finish !
if b = - 1/2 the x^14 terms will 'cancel out' leaving degree 10
No matter WHAT constant 'a' equals, the degree will never be greater than 14
Angle EDC = arctan (sqrt(3)/2) = 40.9 degrees
then angle ECD = 180 - 90 - 40.9 = 49.1 degrees
cos (ECD) = adj / hyp
cos (49.1) = EC / 2
EC = 1.3 units
First ....add the two of the equations together......the 't' will now be gone and you can solve for 's'
use this value of 's' in either of the equations to solve for 't'
Where is 'a' in the equations?
Amount of salt in 4% = .04 x this is the same amount that will be in the final amount
.04x = .06( x %)
.04 = .06 * %
.04/.06 = % = 66.67 % a solution of 67% of the original 4% amount so 33.33% must be removed
Hmmmm..... your question is missing !
I think it is c = 0 then the denominator can never be = 0
8 % of 75% of 'x' is equal to 6
(.08)(.75)x = 6
x = 6/(.08(.75)) = 100 people
Area of triangle = 1/2 b h
= 1/2 (2)(10-p) = 10-p
