ElectricPavlov

as  |x| goes to infinity the fxn approaches zero

  as |x| approaches zero the fxn heads towards infinity

(0,+inf)

16 + 11 - 7 = ___________

x = -y^2 - 3y - 5    is a 'sideways'  parabola...for a line vertical line, x= k ,  to intersect at only ONE point it must intersect at the vertex....find the 'x' value of the vertex:

x = -y^2 - 3y - 5

x = -1(y^2 + 3) - 5

x = - (y+1.5)^2 + 2.25 -5   

x = -(y+1.5)^2 - 2.75                        (h,k) = ( -2.75, -1.5)                      k = - 2.75

The doamain is all 'x' except values that cause denominator of any of the terms to = 0

x cannot equal -8     is all

(- inf, -8) U (-8, + inf)

Two integers are relatively prime if they share no common positive factors (divisors) except 1

for 7    1 2 3 4 5 6 8 9 10 11 12 13     15  16 17 18 19 20   22 23 24 25 26 27     29  30 31 32 33 34    36 37 38 39

USing the above list 

for 10: 1    3             9      11      13                17      19             23                27      29      31      33              37       39     count them up !

2x - 5 <= -x + 12    add x to both sides of the equation

3x -5 <= 12           add 5 to both sides

3x <= 17              divide both sides by 3

x <= 17/3                 

                (-inf, 17/3]

6 out of every 15 have been in an accident

how many 15's are there in 120?       Eight

     8 x  6 = 48  of 120   might have been in anaccident

h = 13 meters

13 = -5t^2 + 20t + 3

-5t^2 + 20t -10 = 0           we can simplify this a bit by dividing through by -5

t^2 -4t +2 = 0         Now use the quadratic formula to find the t values (two of them) ...one will be for the ball on the way UP

                                       the larger one will be for whe the ball is coming DOWN .

a = 1    b= -4    c = 2

\(t = {-(-4) \pm \sqrt{(-4)^2-4(1)(2)} \over 2(1)}\)     I will let you finish.....

Look at the graph and find the point where it is equal to -1    then scan vertically to the x-axis value which will be the value of 'c'

The point    (3, 7 ) should be on the graph    because    (9,7) is  (3^2 , 7)

         sum = 10