\(\sqrt[3]{16}\)= \(\sqrt[3]{8*2}\)= 2 \(\sqrt[3]{2}\) or 2.51984
6^5 * x =20 ???
x=20/7776 = 5/1994
or
6^(5x) = 20 take log of both sides
5x log 6 = log 20
5x= log20/log6
5x=1.67195
x= 0.33439
First, 3u + 3 v = 3 (u+v)
Second u + v = 30 Now multiply both sides by 3
3(u+v) = 3 (30)
3u+3v=90
Sin of theta AND cosine of theta in the THIRD quadrant are BOTH negative !
sin^2 + cos^2 = 1
(3/5)^2 + cos^2 = 1
cos^2 = 1 - (3/5)^2
cos^2 = 1- 9/25
cos^2 = 16/25
cos = + - 4/5
BUT it is in quadrant 3 so it is NEGATIVE cos = - 4/5 AND sin = -3/5
3x^2 - x^3 + 3 = 0 Subtract 3 from both sides
3x^2 - x^3 = -3 Multiply both sides by -1
x^3 - 3x^2 = 3 Factor out x^2
x^2 (x-3) = 3 Divide both sides by x^2
x-3 = 3/(x^2) Add 3 to both sides
x=3+ 3/(x^2)
10-5x=-25 SUbtract 10 from both sides of the equation
-5x = -35 Divide both sides by -5
x = 7
I think you may have written your equation incorrectly...the parentheses are incorrect....and I do not know where the negative sign came from.....
log (( 5/2)^4) / 2 =
4log(5/2) / 2 =
2 log(5/2)
8/25 x 100% = 32%
Here is your answer...use the calculator to compute it
.023 x 6,600,000,000 ==== ?
