We are looking for the time when .1% of the original is left ..... or .001 x original
1/2^n = .001 Log both side
Log(1/2^n) = Log(.001)
n Log1/2 = -3
n = number of half lives = -3/(log(1/2) = 9.965784284 half lives
9.965784284 (5730) = 57103.94394732 years