ElectricPavlov

Wow....a little unclear here.....what is 'E' ??

You didn't give enough information.....haha     DO their ladders reach all of the way to the top????  I hope not!!!!

Perimeter of WHAT???    Need more info please !

Don't overthink it ! LOL   The velocities are just additive   3 + 6 = 9 m/s   

Believe me   ....  I paddled 450 miles of the Yukon River in a canoe two years ago.....it was always GREAT to find a fast current !!!!!!!!

" U "

Correction: I used the wrong coeeficient of friction in my previously posted solution   

    I used 0.4 instead of the stated 0.1  

Here are the corrections:

Friction force =  .1  x 44.55 = 4.455

Required pushing force =  4.455kg + 22.69 = 27.15 kg force

Sorry !!!!!

200 he has  + 200(20) more = 4200 apples..... I hope Alex likes apples!

First figure out the downslope and 'normal' forces of the 50kg mass

Downslope = 50 sin27 = 22.69

Normal      = 50 cos27 = 44.55 kg

Since you are pushing the box UP the hill the force of friction is acting against you ...down the hill

  coeff of fric = .4     .4 x normal force = friction force = .4 (44.55kg) =  17.82 kg

to push the box uphill you must overcome the friction force and the downslope force

Pushing force = 17.82 + 22.69 kg = 40.51 kg force

The first equation can be re-arranged to  y =3x+9     sub this into the second equation for 'y'

-3x -2 (3X+9) =0

-9X-18=0

X= -2

Now sub this value of x into one of the equations to find y

y=3x+9    y= 3(-2)+9 = 3

x,y  =  -2,3

FV=PV (1+i)^n     FV=future value  PV = present value

FV= 900 (1.02)^6 = $ 1013.55