ElectricPavlov

1/3 (28) = 28/3 = 9 1/3

I looked this one up:

V= 5/12 TAN(54)ha^2

Substituting:

5/12 tan(54) (35)(14^2) = 3934.16   units^3      ( I do not know the units in your question)

I THINK you left out an 'x^2' or a 'x'  or both!

x^3 -12 + 16 = x^3 +4

x^3 = -4

x = -1.587

Your method was much simpler !!!   

Sam swims   P +10    while

Tom swims    P-10

Nex Sam has swimmed   3P-80  while

        Tom has swimmed     P+80      Where P = pool length  

Since theyswim at a constant ratio:

(p+10)/(p-10)  =  (3p-80)/(p+80)     cross multiply

p^2 + 80p +10p +800   =  3p^2 -30p -80p +800     simplify

p^2 +90p +800  =   3p^2 -110p +800

90p  = 2p^2 -110p

0= 2p^2 -200p

0= p-100     or  p=100m  = pool length

You are absoutely correct MW !  Don't know what (or why I wasn't) thinking !!!!   LOL      Good job!

I will assume a 'lap' is one length of the pool....

100m

Sam swims  110 m   Tom has only swam  90 m

                     220 m   Tom                         180 m

If the pool is 100   Sam will be 80 meters from the end (on his 3rd lap) as will be Tom (but going opposite direction on his 2nd lap) and they are at the same times.

I'll work on entering here, how I derived it ...if you want it.

Hey Chris......

I agree that it will take the clock this long TO BE CORRECT again, but the question asked what will the REAL time be when the FAULTY clock next displays 10:00.   Yes, I assumed an analog clock (as the question did not specify AM/PM ). 

    Happy Black Friday!

You typed all of this in to ask a question....why not just enter it into the calculator to get an ANSWER?

= 270,000

You're going to have to provide a few more details......  Have any?