COMBINING two of the above answers 2 digits comprise 10 nemerals and 26 letters for each space (36 possibilites for each space) if you disallow special characters (!@#$%^&* etc)
36 x 36 = 1296 possibilities probability of guessing the correct last two digits then becomes 1/1296
Question is unclear in that it does not say WHAT is allowed in the last two digits...numbers only? Letters only? Numbers AND letters only? Special characters??? etc....
YMMV ! LOL