Hmmmm.... I do NOT know if any of these calculations are correct, but here is my try
v = vo + at (1)
t=10.5 sec
+a = 9.81 m/s^2
-a = air resistance = 1.5 m/s^2 x v m/s / 7.5 m/s = .2 v (2)
Substituting into equation (1):
v = 0 + (9.81 - .2v)(10.5) = 103 - 2.1v
v+2.1v = 103
3.1v = 103 or v = 33.225 m/s at 10.5 seconds
Now let's find the height
x = xo + vot + 1/2 at^2 xo and vo are zero for this application, so we are left with
x = 1/2 a t^2
x = 1/2 (9.81 - .2(33.225))(10.5)^2 = 174.47 m (??)
Terminal velocity is where air resistance EQUALS gravity
1.5m/s^2 x v m/s / 7.5m/s = 9.81 m/s^2
.2 v = 9.81
v(terminal) = 9.81 / .2 = 49.05 m/s
I am VERY unsure of ANY of this ...I hope someone will confirm it or laugh out loud at my answers! (I'm almost afraid to post it!)