How high does it go? You can find the max (or min) value of a quadratic by the formula
c-b^2/(4a)
6- (20^2)/(4(-16) = 12.25 feet max height
Time to hit ground
0 = -16t^2+20t+6 (had a typo after the ' 0 ' in my previous answer)
Quadratic Formula yields
t= (-20 +- sqrt(20^2 - 4(-16)(6)) / 2(-16)
= -20 +- 28 / -32 = -.25 or 1.5 sec (Throw out the neg answer....you can't have negative time)
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