Number of unit sold will be 60 - (x-800)/20 where 'x' is the amount over cost
income will be [60-(x-800)/20] * x = [60-x/20 + 800/20] *x = 60x -x^2/20 +40 x
= -x^2/20 +100x
Maximum will occur at - b/2a b = 100 a = 1/20
-(100/(-2/20) )= $ 1000 over cost will maximize profit