sin^2 + cos^2 = 1
so sin = sqrt (1-cos^2)
y = t cos t so y/t =cos t
x = t sin t = t ( sqrt (1- y^2/t^2) ) perhaps? Totally not sure Good luck !
Well, wait a minute...... that was x in terms of y
x/t = sin t y = t (sqrt(1-sin^2 t) = t sqrt(1-x^2/t^2) A shot in the dark !!!