ElectricPavlov

Add 4 to both sides of the equation

3m-4 +4 = -7 + 4

3m = -3      divide both sides by 3

m=-1

y= -1/3(-2)^2

 = -1/3 (4) = -4/3 = - 1 1/3

The question states that the particle     'is moving in uniform acceleration'       It does NOT say that x and y are coordinates, they are distances.

Can you give an example of the problem with which you are dealing?

6 = -log 1/h30      where h3o  is the concentration of H3O

-6 = log 1/h30

10^-6 = 1/h30

1/10^-6 = h30

1 x 10^6   = [H3O]               I hope someone can verify this !

Let's look at the position x   x= vot + 1/2 at^2       vo = original velocity

solve for vo    

vo = x/t- 1/2at

Now, the VELOCITY at x    Vx= vo + at

Substitute for vo  to get 

Vx = (x/t -1/2at) +at

Vx = x/t +1/2at

Now, for y 

y =vt' + 1/2at'2      In THIS instance  the 'v' is Vx which we found above, so let's substitute this into the equation

y= (x/t + 1/2at) t'  + 1/2at'^2   now solve for a

y-xt'/t = 1/2a (tt' +t'2)

2 (y-xt'/t) = a t'(t+t')

a= 2(y-xt'/t) / (t' (t+t') )           Simplify

a= 2(y/t' -x/t) / (t+t')

There are THREE posted rsponses to this question already.

63:9  is a ratio.    Be careful, it is NOT a straight division.     EXAMPLE:    63 red marbles  and 9 blue marbles  is a ratio of 63:9    the PERCENTAGE of RED marbles is NOT  63/9    it is  63 out of the TOTAL (72)    or   63/72 x100%          and the BLUE marbles are NOT 9/63   but 9 out of 72    9/72

The answers..or 'roots' of a quadratic equation of the form  ax^2 + bx + c = 0

2 (x) = 0.9 x + 660     where x=number of b***s of each brand  

x= 600 b***s of each    = 50 dozen of each