1/7 =0.1428571428571429
T the' 2' would be rounded to a '3'
For the equation of a circle the 2250000 = r^2 so r1 = 1500 r2=1700 km
Circumference for r1 = 2 x pi x 1500 km =9424.78 km
r2 = 2 x pi x 1700 = 10681.42
Difference r2 orbit is 1256.64 km longer in one orbit
cubrt (54) = cubrt(27*2) = 3 cubrt 2
cubrt(16) = cubrt (8*2) = 2 cubrt 2
add them together 5 cubrt(2)
F = Gm1m2/r2 G = gravitational constant = 6.67 × 10-11 N-m2/kg2
So let's plug in the numbers
6.67x 10^-11 x 1 x10^6 x 75 x 10^6 / (1 x10^3)^2
= 500.25 x 10^(-11+6+6-6) = 500.25 x 10^-5 N
Area = pi r^2
r^2 = area/pi
r = sqrt(area/pi)
Circ = 2 pi r = 2 pi \(\sqrt{area/pi}\) = 2 sqrt(area x pi^2 /pi ) = 2 \(\sqrt{area*pi}\)
You won't get a numerical answer without more info, but we can get p in terms of x
x-8000 = -20p
8000-x = 20p
p = (8000-x)/20 = 400 - x/20
c^2 = 5c divide both sides by 'c'
c = 5
x^2 + 13x +42 = 0 Use Quadratic formula ...or factor it to
(x+7)(x+6) = 0 so x+7 = 0 means x= -7 x+6 = 0 means x can also = -6
x^2-4x-21 = 0 factors to (x-7)(x+3) = 0 so x = 7 or -3
Let x = 3.2272727272.....
100x = 322.72727272....
10000 x = 32272.72727272...
10000x - 100 x = 9900x = 32272.72727272... - 322,727272... = 31950
x = 31950/9900 = 3 2250/9900= 3 5/22
FV = P ((1+i)^n-1) / i where i = 3%/12 = .0025 n = 12
3000 = P ((1+.0025)^12 -1) / .0025
P =$ 246.58 each month for 12 months
