ElectricPavlov

Perhaps a graphical solution like shown below???

Well....will post graph when uploader is working.....

Hey Guest.....   I think you were probavly the one who solved a similar problem a day or two ago.....can you explain HOW you solve ONE equation with two variable for the two variables?

THIS one:   [127R +14] =[131T + 66], solve for R, T

THANX !!!

Silly question......silly answer:

4xy+-9xy-3xy=  xy ( 4 + (-9) - 3)  = xy (-8) = - 8 xy

n^2 - (n-1)^2  = n^2 - n^2 + 2n -1  = 2n-1

Melody is correct......

Here is another way to look at it

Probability of NOT rolling a 5 on the first roll is 5/6

Probability of NOT rolling a 5 on the second roll is also 5/6

Probability of NOT rolling a 5 in two rolls is then   5/6 x 5/6 = 25 /36

so the probability of  (YES) rolling a 5 is   36/36 - 25/36 = 11/36  with two rolls....

 One of these days I will understand probability.....'probably'? or Maybe ? LOL

(I think !)

1 + 13/100   is just    1 13/100  

= 1+13/100 = 1.13

Quotient =  5 /(-4+(-2))       OR      (-4+(-2))/5   since the question did not specify which was divisor and which was dividend.

Each time you roll the die (one is a 'die'  ...two are called 'dice') you have a 1/6 chance of rolling a '5'

rolling TWO times DOUBLES that chance    2 x 1/6 = 1/3 chance of rolling a '5'

3x4+6-x=5-3

12 + 6 - x = 2

18 -x = 2

18 = 2+x

16 = x