If we take dx/dt of the x= distance equation we will get the velocity = 4t-16 When the car comes to a stop, the velocity = 0 , so setting this equation = 0 will give us t in seconds when the car stops:
4t-16 = 0 yields car stop at t= 4 seconds NOW, going back to the DISTANCE BETWEEN equation with t= 4
x= 2t^2 - 16t +35 yields 32 -64 +35 = 3 meters between the car and the tree...so the car will NOT hit the tree, but stop 3 meters from it.
The distance the car travels is the difference between t= 0 and t= 4 for the distance between equation given
t=0 yields 35 t= 4 we found = 3 35-3 = 32 meters = distance car travelled
