ElectricPavlov

Area x height = volume

24 x (9-4) = 120 cm^3

I think it would be ok ....IF they filter it to show graphs of ONLY MATH POSTS !!!

sqrt(  (-3-4)^2 + (1-10)^2) =  sqrt(49+ 81) = 11.4

1 9/33  =  1 3/11

Hit the ' 2nd ' button first......then the sin button becomes   ' asin '   which is   sin^-1

He could be     1.75/1.08 = 1.62 m

    or             1.75 x 1.08 = 1.89 m

Since it is a right triangle and LN is the hypotenuse:  (your question asks for MN, but I suspect you meant ML)

ln^2 - mn^2 =ml^2    

(sqrt27 + sqrt12)^2 - (sqrt18+sqrt8)^2 = ML^2         Do the math to find  ML

(27+12 + 2 (sqrt(27x12)) - (18+8 + 2 sqrt(18x8)) = ML^2

(39+ 36)  -  (26+ 24) = ML^2

75-50= ML^2

25= ML^2

5 = ML

y=mx+b

you have TWO data points given   (5,9.25)   and  (8, 12.25)

Find slope, m=   (y1-y2) / (x1-x2)

                       (9.25-12.25) / (5-8) = -3/-3 = 1

so   y= mx + b    now becomes  y = (1) x + b    Substitute in one of the points to find  b :

                                                   9.25 = 5 + b       b= 4.25

so your equation is now

y= x + 4.25         which shows the admission is 4.25 and each sample costs 1.00 

-13-2n=-n     add 13 to both sides

-2n=-n+13    add n to both sides

-n=13           Multiply both sides by -1

n= - 13   

F=ma     m=mass is the same on earth as on the moon BUT   a = acceleration is different

moon:  f = 2.26 kg (9.8 m/s^2)(1/6) = 3.69 N