A sequence is 6^(n-1) B sequence is 50(3^(n-1))
Set them equal and solve for n
6^(n-1) = 50(3 ^(n-1))
Take log of both sides
(n-1)Log 6 = Log50 +(n-1)log3
(n-1)(log6-log3) = log 50
n-1 = log50 /(log6-log3)
n = log50/(log6-log3) + 1
n= 6.64 This is where they would EQUAL,,,,the nex integer is where A>B = 7
the integer after which A>B is 6