Well, you got it correct.
50 000 000 watts generated 80 000 watts dissipated in transmission lines. (i^2 r losses)
(50 000 000 - 80 000)/50 000 000 = 99.84 %
8000 x 5100 = 40800000
5200 x 3700 = 19240000
(19240000)/40800000 x 100% = 47.16 %
Probably.
CIRCUMFERENCE = pi x DIAMETER If the hand is 9cm long (from the pivot point)....that is the RADIUS. The DIAMETER is 2 x radius = 18cm
Circumference = pi x 18 = 56.55 cm
3,420,000 = 3.42 x 10^6
n to the second power ...or n squared or \({n}^{2}\)
When you have a QUADRATIC EQUATION in the form ax^2 +bx + c = 0
You can solve for 'x' using the QUADRATIC FORMULA:
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
