Use Quadratic Formula
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\) a = 1 b = (k- 1/k) c = -1
[(1/k - k) +- sqrt ((k-1/k)^2 + 4 ) ] / 2
Substituting thse values in shows that they do not all work....
desmos graphically show 0,0 35, 7 -35, -7
https://www.desmos.com/calculator/tfuqvjljxr
Use the quadratic formula to find the roots
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\) a = 1 b = -6 c = 2
x = 3 +- sqrt 7 real
sqrt(x+3)-1=x
SQRT(X+3) = X+1 SQUARE BOTH SIDES
x+3 = x^2 + 2x + 1 gather like terms
x^2 + x -2 = 0
(x+2)(x-1) = 0 so x = -2 or +1 -2 does not work -throw out
Geometric mean Multiply 'n' numbers together then take the 'nth ' root of the result....
See previous post....
https://web2.0calc.com/questions/please-help-me-graph-the-function-on-the-coordinate
Pick some x values from, say -5 to 5
calculate the f(x) values and plot them, then 'sketch' the graph by connecting the dots....
Here is what it looks like:
https://www.desmos.com/calculator/b79a0cvuku
1 2 3 5 6 7 8 10 11 12 13 25 26 27 28 30 31 32 33 35 36 37 38 count them.....
b b
b w
b g
g b
g w
g g
six choices two are the same 2/6 = 1/3 for same color 2/3 for different colors
Your question is improperly worded and missing information....
