ElectricPavlov

78/100     or      39/50

If Alice ate SIX cakes, she probably has a 'Stomacake'      Hahahaha

Happy Birthday!

30 x (3/5)^0 is the FIRST jump

30 x (3/5)^1  is SECOND jump

30 x (3/5)^2  is third jump

30 x (3/5)^3  is fourth jump

30 x (3/5)^4  is fifth jump

You can 'Brute Force' calculate and add up these numbers, or realize this is a summation of the form:

30 x  \(\sum_{1}^{5}\)(3/5)^(n-1) = 30 (2.3056) = 69.168 cm

30-2(7+2)-1 = 30 - 2(9) - 1 = 30 -18 - 1 = 30 - 19 = 11

Look at it as a RATE problem......

One job = 1

Bill's rate =  1/40  job/minutes

Sue's rate=  1/35 job/minutes

What is the RATE when they BOTH work ?

(1/40 + 1/35)   job/minutes  =  (7+8)/120 = 15/280  Job/minutes

the TIME to complete ONE job = ONE Job / RATE   so, substitute:

1 Job / (15/280 Job/Minutes) = 280/15 minutes = 18.67 minutes

Use Ohm's law   V = I  x  R

V = .00031A  x 3300000 Ohms =  1023 V

"If the expected value of the number shown on a slip randomly drawn from the bag is_____ , then.."

Ya left off the most important part of the question.......shucks.

3 6 12 24 48   = 93   ?

5 terms = 93     yah?   Did I do this correctly?

8.57 = - log [H3O+]
- 8.57 = log [H3O+]
[H3O+] = 10^(-8.57) = 2.692 x 10-9 M

I'll take a stab at it....no guarantee results are correct

Ba++(OH)2   + 2 HCl  =  BaCl2 + 2 H2O 

maybe?