x=position of ball xo= original position of ball vo = original velocity t = time a = acceleration of gravity 9.8 m/s^2
x=xo + vot + 1/2 a t^2 note the vo and a are DOWNWARD in this example and thus NEGATIVE
x = 60 + -3(1) + 1/2 (-9.8)(1^2)
x = 60 -3 -4.9 = 52.1 m above the ground or 7.9 m down from its original position