ElectricPavlov

Find two convenient points  -4,3    4,1

y1-y2   /   x1-x2    =   2/-8   =   - 1/4   slope

From n's height     tan 56 = opp/adj = height above neta  / 150

tan 56 = height/150     height = 222.38 ft

Now add the height below her

tan32 = opp/150       height below =93.73 ft

22.38 + 93.73 ft =..........ft

tan (smallest angle )   = opp/ adj =  5/9

arc tan ( 5/9) =.........

cos (theta) = adj/hyp =  2 sqrt6 / 2 sqrt 15 = sqrt6/sqrt15

arc cos(sqrt6/sqrt15) = 50.8 degrees

12 g = km car can go on g liters

5 1/2 liters =g

12 g  =  12 (5  1/2 ) = 66 km

Via dimensional analysis.....note how things cancel out and you are left with  f / m

15.5  mile / hr    x    1 hr / 60 m      x   5280 ft / mile    =  1364 f / min

https://web2.0calc.com/questions/maths-question_22

1/2   *   9  7/8 =    1/2  * 79/8 = 79/16

rate  * time = distance 

distance/rate = time 

     d = 200

x = original rate

200/x    =   200/(x+5) + 2      solve for x

200 (x+5)  =  200 x  + 2x (x+5)

200x + 1000 = 200x + 2x^2 + 10x

2x^2 +10x -1000 = 0                Use quadratic Formula    x =  20 km/hr   or  -25 (throw out)      Faster speed = 20 + 5 = 25 km/hr

200/20 = 10 hours          200/25 = 8 hours     Check !

I believe Rom ansewered this yesterday, and others have answered it multiple times in the past.....look it up....