make 2x+1 the middle-ish integer the two below will be 2x -1 and 2x -3 above will be 2x +3
2x -3 2x-1 2x+1 2x+3
5 ( 2x-3 + 2x+1) = 22 + (2x-1)(2x+3) + (2x-1 + 2x+3) solve for 'x'
5 ( 4x-2) = 22 + ( 4x^2 +4x-3) + (4x+2)
20x-10 = 22 + 4x^2 +8x -1
0 = 4x^2 - 12x +31 x = hmmmmmmmm non integer
can you clarify this part? ' 22 greater than the product of and the sum of the second and the fourth'