ElectricPavlov

https://web2.0calc.com/questions/pls-help_106

3/5   /   1/3     is the same as        3/5  *   3/1  = 9/5

cos x

reflected

   -cos x

amplitude 5

    -5 cos x

period 6

   -5 cos ( pix/3)

phase shift .25 r

   -5 cos (pi x/3 - pi/12)

78 cents      3 q  + 3 p      or    7 d   8 p

28 cents      1  q    3 p       or    2d    8 p

Need more info re: trajectory of the ball....

p = q + 8     given

p = 5q         given

substitute into the first equation

5q = q + 8

4q = 8

q = 2             so p = 10        2 quarters + 10 pennies = 60 cents

x = k y^3 /z^1/2         not sure how to answer this unless we assume   k y^3  is constant....which is what I'll do...

x = k / z^1/2 

3 = k /(12^1/2)    k = 10.3923

Now when z = 75

x = 10.3923 / (75^1/2) =  1.2

40 b  + 20 n = 130   and

8   b   + 4 n = 28         Multiply this equation by  - 5   then add it to the top one to solve for b, notebooks

                                           then substitute this value of 'b' into one of the equations to solve for 'n'

WAIT a minute !   THIS question makes no sense !     both of the quantities are reduced to 1/5th on the second day, but the amount is not decreased to 1/5th.....no answer .

100,000,000,000,000   is One Hundred Trillion

m * p  = h / (4pi)       if  m is 1/2

1/2 m  * 2p = h/(4pi)       p will double to keep the constant the same....  a 100% increase