Look at your negative z-score table for .0500 (or closest to it) for 5 %
z = -1.65 and - 1.64 are equally apart from .0500
I'll take the average of these two (you may have been instructed to just choose one)
-1.645 standard deviations from the mean of 41
-1.645 ( 9) + 41 = 26.195 is 5th percentile