ElectricPavlov

You answered correctly  

a (x-h)^2 + k

3 (x+2)^2 -8

a = 3    h = -2       k = -8

*** deleted ***

3 (x^2+4x)  + 4            "complete the square for x "

3 (x+2)^2  - 12 + 4

3(x+2)^2 - 8

DEC = 180 - 118 = 62^o

Then all the angles of a triangle sum to 180^o

3y+5       +     8y+3       + 62      = 180     You should be able to get it from here...!  

5w-10  =  -3 (w-2)

5w-10  = -3w + 6

8w = 16

w=2

s₁= s₂-5

s₃= 3 + (s₂-5) = s₂-2

s2-5     +   s2      +     s2 - 2    =   3 s2-7       = 17      

                                                       s2 = 8

                                                       s1= 3

                                                        s3 = 6   in

For the top portion find the slant height of the cone      s = sqrt (4^2 +5^2) = sqrt41

surface area = pi  r   s       for the cone portion     r = 4  s = sqrt41

For the cylinder area = pi r^2 h      r = 4  h = 8  

Add the two areas together to get total area    cm²

For x    from 3 to -2    is   -5            2/3*(-5)= -10/3     add to 3     = -1/3

for y     from  -1  to 3   is 4               2/3*4    = 8/3       add to -1     = 5/3

arctan ( 15.1/9.4)