(1) y=x-2
(2) 2x+2y=4
insert (1) in (2)
2x+2(x-2)=4
2x+2x-4 =4
4x-4=4 |+4
4x=8 |:4
x=2
insert x in (1)
y=2-2
y=0
I have the points S1 and S2 is calculated and noted that the ellipse has to look like this.
the ellipse with foci F1(1,-4) and F2(5,-4) that passes through the point (3,2)
Given V=3.14r^2h isolate h (step by step)
x+3(x-6)=2x-3
x+3x-18=2x-3
4x-18=2x-3 |-2x
2x-18= -3 |+18
2x = 15 | : 2
x = 7,5
A 4" by 6" by 8" rectangular solid is cut by slicing through the midpoint of three adjacent edges. What is the number of inches in the sum of the lengths of the edges of the tetrahedron that is cut?
I would really appreciate it if you guys could help me out as I am very bad at math!
Say thank you
\(\sqrt{2}\) = 1.414213562373095...
1.414213562373095 * 2 = 2.82842712474619
2.82842712474619 * 64 = 181.01933598375616
2) x + y = 120 (1)
x - y = 50 | + y (2)
x = 50 + y
x in (1)
50 + y + y = 120
50 + 2y = 120 | - 50
2y = 70 | : 2
y = 35
y in (1)
x + 35 = 120 | - 35
x = 85
1) 5x - 7 = 3x + 11 | - 3x
2x - 7 = 11 | + 7
2x = 18 | : 2
x = 9
