3*3*3*5*5*5
\(\frac{2x^2+5x-3}{2x^2+7x+3}=\frac{2(x+3)(x-0,5)}{2(x+3)(x+0,5)}=\frac{x-0,5}{x+0,5}\)
if ac=5x-16 and cf=2x-4 then what af =?
\(a=\frac{5x-16}{c}\)
\(f=\frac{2x-4}{c}\)
\(a*f=\frac{5x-16}{c}*\frac{2x-4}{c}\)
\(a*f=\frac{(5x-16)*(2x-4)}{c^2}\)
\(a*f=\frac{10x^2-52x+64}{c^2}\)
K'(x)=0,2x
Die 0,1 muss ja mit der 2 multipliziert erden. Man braucht schon einen Wert für K(x), um x ermitteln zu können.
Wie groß ist K(x)?
K(x)=50+0,1x² |-50
0,1x2=K(x)-50 |:0,1
x2= (K(x)-50)/0,1
\(x=\sqrt{}\frac{K(x)-50}{0,1}\)
17-3-1=13
20-16-1=3
simplify
secx-sinxtanx
Here is the answer
A sphere has a volume of 356 cm3. Calculate the surface area of the sphere. pls help
Given: Line AG and Line IC are common internal tangents of center point H and center point B. If Line BC=4 and Line EF=1 and Line EF= Line ED. What is the measure of Line EG?
Looks like this???
You have to send a picture!
