amnesia

Jup it is 56.5 km^2. At least referring to wikipedia. I actually dont need any correct answer, just a value that gets near the 550 Gw/h. I mean, the formula 0.5*A*p*h^2*g describes the maximal potential Energy in one high tide, meaning it cant get over this value. Either theres a mistake in my logic or calculation or the values given by wiki are wrong. only thing that would come to mind are the difference in high tides during the year between springtide and nipptide and difference in position between moon, sun and earth...

converted 565 km^2 *

Oh jea, your right. I only converted 5.6 km^2 while it is 56 km^2. Mhmm that makes my calculation even more irritating having only 5.4Gw/h with one high or 10.8 Gw/h with two highes.

Im still editing too much, welp cant edit my first post thou since its a reply.

I didnt multpiplied it by two, but i mentioned it in my main post  in the last sentence. But still with multiplying it doesnt get close to the 550 Gw/h stated on wiki. Also where did u get the 64 and 8^2 in ur first reply? Shouldnt there be only one squared tidal high? 

Jup, its 8 meters. I squared 8, so it gave me the 64 in my calculation. I also transfered every unit into meter. I used the sample calculation as a refference. I didnt  divided it by  86400 seconds, as i didnt wanted mw/day, but gw/h to get a better refference.

I got the equation from many reliable resources, also the one you linked :)

Well lets try to look at the exponent x.

Exponential growth means with x going to positive infinity, y increases.

exponential decay then means the opposite, with x going to positive infinity, y decreases.

We got y = (1/6)^x 

Does y increases or decreases, with an increasing x?

I guess u can answer that question urself :)

(1/6)^1 > (1/6)^2

Scientific Notation is just an other way to write a number with a 10^x. U can add, subtract, multiply, divide this number as every other normal numbers, as the value doesnt change.

F.x. 1.2 * 10^3 is a scientific notation of the number 1200. 

This is really helpful when numbers get large or have many decimals, specialy in physics.

Hey sorry for that late response. Well first off thanks for ur answer :) Gotta check it through another time thou 

I think the App is not the same as the web calculator. So Im pretty sure its a one price for the app.

\(\frac{48}{2}*(9+3) is not \frac{48}{2*(9+3)}\)

But the way you wrote it, its the same.