Let P (n) denote the number of factors of n. Find all values of n which satisfy P(n) = n.
n = 1 1 factor: 1
n = 2 2 factors: 1, 2
n = 3 2 factors
n = 4 3 factors: 1, 2, 4
n = 5 2 factors
n = 6 4 factors: 1, 2, 3, 6
n = 7 2 factors
n = 8 4 factors: 1, 2, 4, 8
n = 9 2 factors
n = 10 4 factors: 1, 2, 5, 10
n = 11 2 factors
n = 12 6 factors: 1, 2, 3, 4, 6, 12
Those two are all I can think of. As n gets larger, P(n) sometimes gets larger,
but I think the trending demonstrates that P(n) is never going to catch up to n.
.