BuilderBoi

The message wasn't directed to you, it was to catmg. 

You already said you were in 7th grade like me :)

uh... I only know sin, cos, and tan... I have no clue what sec and cosec are

Sorry lol!

Maybe someone else can help...

If you're comfortable Cat, what grade are you in?

I'm in 7th btw.

The rectangular base has an area \(20 \times 15 = 300\)

The triangles have an area \(20 \times 8 \div 2 = 80\)

Thus the area is \(300 + 80 = \color{brown}\boxed{380}\)

k has to be negative, so the answer is \(\color{brown}\boxed{1 - 4 \sqrt7}\)

Here is the graph: https://www.desmos.com/calculator/fwa8nyw6it

It has to be negative, so, unfortunately, you're not right. But, good try tho!

There are 6 x 6 = 36 options

Of these, 14 of them work: 

1 + 4

4 + 1

3 + 2 

2 + 3 

6 + 9

9 + 6

7 + 8

8 + 7

11 + 4

4 + 11

3 + 12

12 + 3

10 + 5

5 + 10

Thus, the probability is \({14 \over 36} = \color{brown}\boxed{7 \over 18}\)

Problem 3: The height of \(\triangle {XYD} \) must be at most 4. 

Shading all the points that work, we can find the area of the shaded region over the area of the entire triangle. 

The area of the entire triangle is 36, and the area of the shaded region is 20. 

Thus the probability is \({20 \over 36 } = \color{brown}\boxed{5 \over 9}\)

Here is the image: 

Note: You will get the same answer if you swap the height and width of the triangle. 

same lol

But, a square is technically a rectangle... So your answer would still be right.