BuilderBoi

Because the lines are perpendicular, the other line has a slope of \(5\).

This means that the equation is \(y = 5x + b\)

Plugging in the point (8, 3), we get: \(3= 40+b\), meaning \(b = -37\)

Now, we have to convert \(y = 5x - 37\) into standard form. 

Subtracting \(5x\) from both sides, we get \(-5x + y = -37\)

Multiplying the equation by \(-{16 \over 5}\) , we get: \(16x-3.2y=118.4\)

From here, we can find the pair to be \(\color{brown}\boxed{(-3.2, 118.4)}\)

Here: https://web2.0calc.com/questions/help_84215

The fourth is B

The fifth is E

The third is C

The second is A

The first is D

i think...

wdym vin, they're totally original...

In that question, the answerer leads to the right answer, but they fail to consider that the numbers chosen don't have to be an integer. 

For the product to be positive, we need both x and y to be negative. 

X is gauarnteed to be negative, and Y  has a \(2 \over 3\) chance of being negative. 

Thus, the probability is \(1 \times {2 \over 3} = \color{brown}\boxed{2 \over 3}\)

Yea, he's right because square's always maximize the area;

The slope of the line is \({{2 - 5 } \over {1.5+2}} = -{6 \over 7}\)

Plugging this into slope-intercept form, we have: \({35 \over 7} = {12 \over 7} + b\), meaning the y-intercept is \({23 \over 7}\)

Thus, our equation is: \(y = -{6 \over 7}x + {23 \over 7}\)

To convert it to standard form, add \({6 \over 7}x\) to both sides, giving us: \(y + {6 \over 7}x = {23 \over 7}\)

Multiply this by 7, giving us: \(\color{brown}\boxed{7y+6x=23}\)

I think I solved for a - 2b, and you solved for a + 2b

Wait, isn't it a -2b...