civonamzuk

A(-2, 1)

M(1, -6)

B(4, -13)

4 + (-13) = -9

Angle YZX = 180 - (70 + 50) = 60º

Perimeter = 4√15 + 4√5 + 8√5

24(3x - 21) = 27(x + 13)

72x - 504 = 27x + 351

45x = 855

x = 19

2x + 13 = 15

x = 1

5y - 36 = y

y = 9

correction...

[ABCD] = 2 * { (28/2) * [(√1173) / 2]} 

a = 48 / (36/48) = 64

b = sqrt(48² + 36²) = 60

c = (48b) / 36 = 80

P = 148          Short diagonal = 28

Long diagonal = 2[sqrt(148/4)² - (28/2)²] = √1173

[ABCD] = (28/2) * [(√1173) / 2]

5x - 2 + 2x + 8 = 90

7x = 84

x = 12

I knew that something was missing... Here's the whole question:

A solid sculpture consists of a 4x4x4 cube with a 3x3x3 cube sticking out, as shown. Three vertices of the smaller cube lie on the edges of the larger cube, the same distance along each.
What is the total volume of the sculpture?

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

1/3(3²/2 * 3) = 4.5 cubic units

Smaller cube   V₃ = 3³ = 27

Larger cube     V₄ = 4³ = 64

Total volume    V_t = (27 + 64) - 2(4.5) = 82 cubic units