civonamzuk

Max  Perimeter = 100 + 2(25√8)

Either increasing the radius or the height of a cylinder by six inches will result in the same volume. The original height of the cylinder is four inches. What is the original radius in inches?

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

V = r²*pi*h

(6+r)² *pi * 4 = r² * pi * 10

The original radius=>    r = 2(2 + √10)

Semi perimeter = 30/2

Area = sqrt[s(s-a)(s-b)(s-c)

Inradius = A/s

Circumradius (R) = (a*b*c) / (4*r*s)

R = 6.5

This is very simple...

[LPQ] = √20(3√20)

[LPQ] / [JKL] = 3/16

[PQR] / [JKL] = 1/16

CD = sqrt(BC² - BD²)

sin(B) = CD / BC

Let ABC be the right-angled isosceles triangle with angle A = 90 degrees.

AM = BM = √50

MD = 1/2(AM)

Angle AME = 45º

Tangent of angle BDM = 2

Find TD and TM, and then using Heron's formula, calculate the area of triangle DME. 

MN is NOT equal to 10 !!! 

MN = 14 / 2 = 7 !!! 

Radii are 7, 7, and 11 

Good job!!! 

Angle EDF = 1/2(180 - 32)